ListAGG no servidor SQL
sabes fazer a mesma função ou outro método?
Por Exemplo,
Field A | Field B
1 | A
1 | B
2 | A
e eu gostaria que o resultado desta consulta fosse
1 | AB
2 | A
4 answers
A partir de SQL Server 2017 a função STRING_AGG
está disponível, o que simplifica consideravelmente a lógica:
select FieldA, string_agg(FieldB, '') as data
from yourtable
group by FieldA
Ver Violino SQL com demonstração
No servidor SQL pode usar FOR XML PATH
para obter o resultado:
select distinct t1.FieldA,
STUFF((SELECT distinct '' + t2.FieldB
from yourtable t2
where t1.FieldA = t2.FieldA
FOR XML PATH(''), TYPE
).value('.', 'NVARCHAR(MAX)')
,1,0,'') data
from yourtable t1;
MySQL
SELECT FieldA
, GROUP_CONCAT(FieldB ORDER BY FieldB SEPARATOR ',') AS FieldBs
FROM TableName
GROUP BY FieldA
ORDER BY FieldA;
Oracle & DB2
SELECT FieldA
, LISTAGG(FieldB, ',') WITHIN GROUP (ORDER BY FieldB) AS FieldBs
FROM TableName
GROUP BY FieldA
ORDER BY FieldA;
PostgreSQL
SELECT FieldA
, STRING_AGG(FieldB, ',' ORDER BY FieldB) AS FieldBs
FROM TableName
GROUP BY FieldA
ORDER BY FieldA;
Servidor SQL
SQL Server ≥ 2017 & Azure SQL
SELECT FieldA
, STRING_AGG(FieldB, ',') WITHIN GROUP (ORDER BY FieldB) AS FieldBs
FROM TableName
GROUP BY FieldA
ORDER BY FieldA;
SQL Server ≤ 2016 (CTE incluído para incentivar o princípio da seca )
WITH CTE_TableName AS (
SELECT FieldA, FieldB
FROM TableName)
SELECT t0.FieldA
, STUFF((
SELECT ',' + t1.FieldB
FROM CTE_TableName t1
WHERE t1.FieldA = t0.FieldA
ORDER BY t1.FieldB
FOR XML PATH('')), 1, LEN(','), '') AS FieldBs
FROM CTE_TableName t0
GROUP BY t0.FieldA
ORDER BY FieldA;
SQLite
A encomenda requer um CTE ou subquery
WITH CTE_TableName AS (
SELECT FieldA, FieldB
FROM TableName
ORDER BY FieldA, FieldB)
SELECT FieldA
, GROUP_CONCAT(FieldB, ',') AS FieldBs
FROM CTE_TableName
GROUP BY FieldA
ORDER BY FieldA;
Sem pedir
SELECT FieldA
, GROUP_CONCAT(FieldB, ',') AS FieldBs
FROM TableName
GROUP BY FieldA
ORDER BY FieldA;
No servidor SQL 2017 STRING_AGG é adicionado:
SELECT t.name,STRING_AGG (c.name, ',') AS csv
FROM sys.tables t
JOIN sys.columns c on t.object_id = c.object_id
GROUP BY t.name
ORDER BY 1
Also, STRING_SPLIT is usefull for the opposite case and available in SQL Server 2016
Antes da existência da função SQL * Server 2017 string_agg ..
(isto é, devolve apenas uma linha ..)
select distinct
SUBSTRING (
stuff(( select distinct ',' + [FieldB] from tablename order by 1 FOR XML PATH(''), TYPE).value('.', 'NVARCHAR(MAX)')
,1,0,'' )
,2,9999)
from
tablename
Por exemplo, devolve valores separados por vírgulas A, B